1. Tardigrade
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  3. Physics
  4. Tuning fork F1 has a frequency of 256 Hz and it is observed to produce 6 beats/second with another tuning fork F2. When F2 is loaded with wax, it still produces 6 beats/second with F1. The frequency of F2 before loading was

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Q. Tuning fork $F_{1}$ has a frequency of $256\, Hz$ and it is observed to produce 6 beats/second with another tuning fork $F_{2}$. When $F_{2}$ is loaded with wax, it still produces 6 beats/second with $F_{1}$. The frequency of $F_{2}$ before loading was

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Solution:

$n_{A}=$ Known frequency $=341\, Hz ,\, n_{B}=$ ?
$x=6$ bps, which is decreasing (i.e., $x \downarrow)$ after loading (from 6 to 1 bps)
$x=6$ bps, which remains the same after loading.
Unknown tuning fork $F_{2}$ is loaded so $n_{B} \downarrow$
Hence $n_{A}-n_{B} \downarrow=x \ldots$ (i) Wrong
$n_{B} \downarrow-n_{A}=x \ldots$ (ii) Correct
$\Rightarrow n_{B}=n_{A}+x=256+6=262\, Hz$