Question

Total number of $H^{+}$ ions present in $10mL$ of a solution having $pH=10$ is:

• A. $10^{10}$
• B. $10^{-10}$
• C. $6.02\times 10^{23}$
• D. $6.02\times 10^{11}$

Answer 1

Answer: (D)

$pH=10\Rightarrow \left[H^{+}\right]=10^{-10}mol{L}^{-1}$
$No.of$ $H^{+}\text{in }10mL$
$=\frac{10}{1000}\times 6.02\times 10^{23}\times 10^{-10}=6.02\times 10^{11}$