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Q. Total number of $H^{+}$ ions present in $10\,mL$ of a solution having $pH=10$ is:

NTA AbhyasNTA Abhyas 2022

Solution:

$pH=10\Rightarrow \left[H^{+}\right]=10^{- 10}molL^{- 1}$
$No.of$ $H^{+}\text{in }10mL$
$=\frac{10}{1000}\times 6.02\times 10^{23}\times 10^{- 10}=6.02\times 10^{11}$