Q.
Total number of geometrical isomers shown by compounds (A) is__________.
44
139
Organic Chemistry – Some Basic Principles and Techniques
Report Error
Answer: 3
Solution:
In this case, terminal groups are same.
No. of double bonds n=2.
No. of G.I.=2n−1+2n/2−1 =21+20=3
Following are the 3 structures:
But (iii) and (iv) are same structures. Hence, 3 geometrical isomers are possible.
