Question

Total number of 6-digit numbers in which only and all the five digits 1, 3, 5, 7 and 9 appear, is :

• A. $5^6$
• B. $\frac{1}{2}\left(6!\right)$
• C. $6!$
• D. $\frac{5}{2}\left(6!\right)$

Answer 1

Answer: (D)

Total number of 6-digit numbers in which only and all the five digits 1, 3, 5, 7 and 9 is
${}^5{C}_1\times \frac{6!}{2!}$