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  4. Total number of 6-digit numbers in which only and all the five digits 1, 3, 5, 7 and 9 appear, is :

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Q. Total number of 6-digit numbers in which only and all the five digits 1, 3, 5, 7 and 9 appear, is :

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Solution:

Total number of 6-digit numbers in which only and all the five digits 1, 3, 5, 7 and 9 is
$^{5}C_{1} \times \frac{6!}{2!}$