Q.
Tom and Dick are running forward with the same speed. They are throwing a rubber ball to each other at a constant speed v as seen by the thrower. According to Sam who is standing on the ground the speed of ball is
Let vBG be the velocity of ball w.r.t. ground, vBT be the velocity of ball w.r.t. thrower
and vTG be the velocity of thrower w.r.t. ground.
Then vBG=vBT+vTG
Here, vTG>0
Therefore, velocity of the ball w.r.t. ground will be greater than velocity of ball w.r.t. thrower.