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Q. Tom and Dick are running forward with the same speed. They are throwing a rubber ball to each other at a constant speed v as seen by the thrower. According to Sam who is standing on the ground the speed of ball is

Delhi UMET/DPMTDelhi UMET/DPMT 2009

Solution:

Let $v_{B G}$ be the velocity of ball w.r.t. ground,
$v_{B T}$ be the velocity of ball w.r.t. thrower
and $v_{T G}$ be the velocity of thrower w.r.t. ground.
Then $\vec{v}_{B G}=\vec{v}_{B T}+\vec{v}_{T G}$
Here, $\vec{v}_{T G}>0$
Therefore, velocity of the ball w.r.t. ground will be greater than velocity of ball w.r.t. thrower.