Question

Time required to deposit $200g$ of $Al$ from an electrolytic cell containing $A{l}_2{O}_3$ using a current of $150$ ampere is

Answer 1

Answer: 14296.29

The reaction is, ${\left(A{l}^{3+}\right)}_2+6e\to 2Al$

$\therefore E_{Al}=$ Atomic mass $/3=27/3=9$

Now, $m=E..i.t/96500$

$200=\frac{27\times 150\times t}{3\times 96500}$

$\therefore t=14296.29$ seconds