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  4. Time required to deposit 200 g of Al from an electrolytic cell containing Al 2 O 3 using a current of 150 ampere is

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Q. Time required to deposit $200\, g$ of $Al$ from an electrolytic cell containing $Al _{2} O _{3}$ using a current of $150$ ampere is

Electrochemistry

Solution:

The reaction is, $\left( Al ^{3+}\right)_{2}+6 e \rightarrow 2\, Al$

$\therefore E _{ Al }=$ Atomic mass $/3=27 /3=9$

Now, $m = E ..i.\, t/96500$

$200=\frac{27 \times 150 \times t}{3 \times 96500}$

$\therefore t=14296.29$ seconds