Through two parallel wires A and B,10 and 2 ampere of currents are passed respectively in opposite direction. If the wire A is infinitely long and the length of the wire B is 2m, the force on the conductor B, which is situated at 10cm distance from A will be :-

Question

Through two parallel wires A and B,10 and 2 ampere of currents are passed respectively in opposite direction. If the wire A is infinitely long and the length of the wire B is 2m, the force on the conductor B, which is situated at 10cm distance from A will be :- (A) 8× 10- 5N (B) 4× 10- 7N (C) 4× 10- 5N (D) 4π × 10- 7N

Tardigrade Admin · Accepted Answer

F=((μ )0/4 π )⋅ (2 i1 i2/a)× 1⇒ F=(10)- 7× (2 × 10 × 2/(10 × (10)- 2))× 2=8× (10)- 5N

Q. Through two parallel wires $A$ and $B, 10$ and $2$ ampere of currents are passed respectively in opposite direction. If the wire A is infinitely long and the length of the wire $B$ is $2 m,$ the force on the conductor $B,$ which is situated at $10 c m$ distance from $A$ will be :-

$8 \times 1 0^{- 5} N$

$4 \times 1 0^{- 7} N$

$4 \times 1 0^{- 5} N$

$4 π \times 1 0^{- 7} N$

$F = \frac{( μ ) _{0}}{4 π} \cdot \frac{2 i _{1} i _{2}}{a} \times 1 \Rightarrow F = (10)^{- 7} \times \frac{2 \times 10 \times 2}{( 10 \times ( 10 ) ^{- 2} )} \times 2 = 8 \times (10)^{- 5} N$

Q. Through two parallel wires A and B,10 and 2 ampere of currents are passed respectively in opposite direction. If the wire A is infinitely long and the length of the wire B is 2m, the force on the conductor B, which is situated at 10cm distance from A will be :-

8×10−5N

4×10−7N

4×10−5N

4π×10−7N