Question

Three resistances each of 8$\Omega$ are connected to form a triangle. The resistance between any two terminals is

• A. 12 $\Omega$
• B. 2 $\Omega$
• C. 6 $\Omega$
• D. $\frac{16}{3}\Omega$

Answer 1

Answer: (D)

In this case, two resistances are in series and third is in parallel to them. Therefore, net resistance is given by
$\frac{1}{R}=\frac{1}{6}+\frac{1}{8}=\frac{3}{16}$
$\therefore$ R = $\frac{16}{3}\Omega$