Question

Three resistances each of 8$\Omega$ are connected to form a triangle. The resistance between any two terminals is

• A. 12 $\Omega$
• B. 2 $\Omega$
• C. 6 $\Omega$
• D. $\frac {16}{3}\,\, \Omega$

Answer 1

Answer: (D)

In this case, two resistances are in series and third is in parallel to them. Therefore, net resistance is given by
$\frac{1}{R} = \frac{1}{6} + \frac{1}{8} = \frac{3}{16}$
$\therefore $ R = $\frac{16}{3} \Omega$