Question

Three resistances are connected to form the sides of a triangle $ABC,$ the resistance of the sides $AB,BC$ and $CA$ are $40\Omega ,60\Omega$ and $100\Omega$ respectively. The effective resistance between the points $A$ and $B$ in ohm will be

• A. 32
• B. 64
• C. 50
• D. 200

Answer 1

Answer: (A)

Here, $40\Omega$ is in parallel with $(100+60)\Omega$.
So, effective resistance between $A$ and $B$ is
$=\frac{40\times (100+60)}{40+(100+60)}=32\Omega$