Three identical capacitors are first connected in series and then in parallel. The ratio of effective capacitances in two cases is

Question

Three identical capacitors are first connected in series and then in parallel. The ratio of effective capacitances in two cases is (A)  9: 1  (B)  3: 1  (C)  1: 3  (D)  1: 9

Tardigrade Admin · Accepted Answer

Let capacitance of each capacitor be C. When three capacitors are connected in series then equivalent capacitance is given by (1/CS) = (1/C) + (1/C) + (1/C) or CS = (C/3) When three capacitors are connected in parallel then equivalent capacitance is given by, CP = C + C+ C = 3C Required ratio = (CS/CP) = (C 3/3C) = (1/9)

Q. Three identical capacitors are first connected in series and then in parallel. The ratio of effective capacitances in two cases is

$9 : 1$

$3 : 1$

$1 : 3$

$1 : 9$

Q. Three identical capacitors are first connected in series and then in parallel. The ratio of effective capacitances in two cases is

9:1

3:1

1:3

1:9

$9 : 1$

$3 : 1$

$1 : 3$

$1 : 9$