Three charges each equal to +2 C, are placed at the corners of an equilateral triangle. If the force between any two charges be F, then the net force on a single charge will be

Question

Three charges each equal to +2 C, are placed at the corners of an equilateral triangle. If the force between any two charges be F, then the net force on a single charge will be (A) 3 F (B) 2 F (C) √2 F (D) √3 F

Tardigrade Admin · Accepted Answer

F text net =√F2+F2+2 F ⋅ F ⋅ cos 60° =√F2+F2+2 F2((1/2)) =√3 F2=F √3 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7e4dbbb4bb629ad185c63dc7db6e1c44-.png" />

Q. Three charges each equal to $+ 2 C$ , are placed at the corners of an equilateral triangle. If the force between any two charges be $F$ , then the net force on a single charge will be

$3 F$

$2 F$

$2 F$

$3 F$

$F_{net} = F^{2} + F^{2} + 2 F \cdot F \cdot cos 6 0^{\circ}$
$= F^{2} + F^{2} + 2 F^{2} (\frac{1}{2})$
$= 3 F^{2} = F 3$

Q. Three charges each equal to +2C, are placed at the corners of an equilateral triangle. If the force between any two charges be F, then the net force on a single charge will be

3F

2F

2​F

3​F

Fnet ​=F2+F2+2F⋅F⋅cos60∘​ =F2+F2+2F2(21​)​ =3F2​=F3​

Q. Three charges each equal to $+ 2 C$ , are placed at the corners of an equilateral triangle. If the force between any two charges be $F$ , then the net force on a single charge will be

$3 F$

$2 F$

$2 F$

$3 F$

$F_{net} = F^{2} + F^{2} + 2 F \cdot F \cdot cos 6 0^{\circ}$
$= F^{2} + F^{2} + 2 F^{2} (\frac{1}{2})$
$= 3 F^{2} = F 3$