Three cells of emf 2 V , 3 V and 4 V are connected in parallel as shown in the figure. If their internal resistances are 1 Ω, 1 Ω and 2 Ω respectively, then the current through the external load resistance R is

Question

Three cells of emf 2 V , 3 V and 4 V are connected in parallel as shown in the figure. If their internal resistances are 1 Ω, 1 Ω and 2 Ω respectively, then the current through the external load resistance R is (A) 0.5 A (B) 0.2 A (C) 0.4 A (D) 1.0 A

Tardigrade Admin · Accepted Answer

(Ee q/Re q)=(E1/r1)+(E2/r2)+(E3/r3) Ee q=(2+3-2) × (2/5) = (6/5) V i= ((6/5)/(2)5+2)=((6/5)/(12)5) = 0.5 A

Q. Three cells of emf $2 V, 3 V$ and $4 V$ are connected in parallel as shown in the figure. If their internal resistances are $1 Ω, 1 Ω$ and $2 Ω$ respectively, then the current through the external load resistance $R$ is

0.5 A

0.2 A

0.4 A

1.0 A

$\frac{E _{e q}}{R _{e q}} = \frac{E _{1}}{r _{1}} + \frac{E _{2}}{r _{2}} + \frac{E _{3}}{r _{3}}$
$E_{e q} = (2 + 3 - 2) \times \frac{2}{5}$
$= \frac{6}{5} V$
$i = \frac{\frac{6}{5}}{\frac{2}{5} + 2} = \frac{\frac{6}{5}}{\frac{12}{5}}$
$= 0.5 A$

Q. Three cells of emf 2V,3V and 4V are connected in parallel as shown in the figure. If their internal resistances are 1Ω,1Ω and 2Ω respectively, then the current through the external load resistance R is