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Q. Three cells of emf $2\, V , 3\, V$ and $4\, V$ are connected in parallel as shown in the figure. If their internal resistances are $1 \,\Omega, 1\, \Omega$ and $2\, \Omega$ respectively, then the current through the external load resistance $R$ isPhysics Question Image

Solution:

$ \frac{E_{e q}}{R_{e q}}=\frac{E_{1}}{r_{1}}+\frac{E_{2}}{r_{2}}+\frac{E_{3}}{r_{3}} $
$ E_{e q}=(2+3-2) \times \frac{2}{5} $
$= \frac{6}{5} V $
$ i= \frac{\frac{6}{5}}{\frac{2}{5}+2}=\frac{\frac{6}{5}}{\frac{12}{5}} $
$= 0.5\, A $