Three capacitors of capacitance 3 μ F , 10 μ F and 15 μ F are connected in series to a voltage source of 100 V. The charge on 15 μ F is

Question

Three capacitors of capacitance 3 μ F , 10 μ F and 15 μ F are connected in series to a voltage source of 100 V. The charge on 15 μ F is (A) 50 μ C (B) 100 μ C (C) 200 μ C (D) 280 μ C

Tardigrade Admin · Accepted Answer

(1/Ce q)=(1/3)+(1/10)+(1/15) ⇒ Ce q=2 μ F Charge on each capacitor Q=Ce q × V ⇒ Q =2 × 100=200 μ C

Q. Three capacitors of capacitance $3 μ F, 10 μ F$ and $15 μ F$ are connected in series to a voltage source of $100 V$ . The charge on $15 μ F$ is

$50 μ C$

$100 μ C$

$200 μ C$

$280 μ C$

$\frac{1}{C _{e q}} = \frac{1}{3} + \frac{1}{10} + \frac{1}{15}$
$\Rightarrow C_{e q} = 2 μ F$
Charge on each capacitor
$Q = C_{e q} \times V \Rightarrow Q$
$= 2 \times 100 = 200 μ C$

Q. Three capacitors of capacitance 3μF,10μF and 15μF are connected in series to a voltage source of 100V. The charge on 15μF is

50μC

100μC

200μC

280μC