Three capacitors each of capacity 4 μ textF are to be connected in such a way that the effective capacitance is 6 μ textF . This can be done by

Question

Three capacitors each of capacity 4 μ textF are to be connected in such a way that the effective capacitance is 6 μ textF . This can be done by (A) Connecting two in parallel and one in series (B) Connecting all of them in series (C) Connecting them in parallel (D) Connecting two in series and one in parallel

Tardigrade Admin · Accepted Answer

For series, Cs e r i e s=(C1 C2/C1 + C2)=(4 × 4/4 + 4)=2μ F After connecting two capacitors in series and then connecting in parallel, Cs e r i e s+C=2+4=6μ F Solution

Q. Three capacitors each of capacity $4 μ F$ are to be connected in such a way that the effective capacitance is $6 μ F$ . This can be done by

Connecting two in parallel and one in series

Connecting all of them in series

Connecting them in parallel

Connecting two in series and one in parallel

For series, $C_{ser i es} = \frac{C _{1} C _{2}}{C _{1} + C _{2}} = \frac{4 \times 4}{4 + 4} = 2 μ F$
After connecting two capacitors in series and then connecting in parallel, $C_{ser i es} + C = 2 + 4 = 6 μ F$

Q. Three capacitors each of capacity 4μF are to be connected in such a way that the effective capacitance is 6μF . This can be done by