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  4. Three capacitors each of capacity 4 μ textF are to be connected in such a way that the effective capacitance is 6 μ textF . This can be done by

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Q. Three capacitors each of capacity $4 \, μ \text{F}$ are to be connected in such a way that the effective capacitance is $6 \, μ \text{F}$ . This can be done by

NTA AbhyasNTA Abhyas 2022

Solution:

For series, $C_{s e r i e s}=\frac{C_{1} C_{2}}{C_{1} + C_{2}}=\frac{4 \times 4}{4 + 4}=2\mu F$
After connecting two capacitors in series and then connecting in parallel, $C_{s e r i e s}+C=2+4=6\mu F$
Solution