Question

Thermal capacity of 40 g of aluminum
(s = 0.2 cal/g K) is

• A. 168 J/K
• B. 672 J/K
• C. 840 J/K
• D. 33.6 J/K

Answer 1

Answer: (D)

Thermal capacity = ms = 40 $\times 0.2=8cal{/}^{0}K$
$8cal=4.2\times 8J=33.6joule{/}^{0}K.$