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  4. Thermal capacity of 40 g of aluminum (s = 0.2 cal/g K) is

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Q. Thermal capacity of 40 g of aluminum
(s = 0.2 cal/g K) is

AIPMTAIPMT 1990

Solution:

Thermal capacity = ms = 40 $\times 0.2=8 \, cal/^0K$
$8 \, cal=4.2 \times 8 \, J=33.6 \, joule/^0K. $