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Question
Physics
Thermal capacity of 40 g of aluminum (s = 0.2 cal/g K) is
Q. Thermal capacity of 40 g of aluminum
(s = 0.2 cal/g K) is
5001
202
AIPMT
AIPMT 1990
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A
168 J/K
15%
B
672 J/K
19%
C
840 J/K
28%
D
33.6 J/K
38%
Solution:
Thermal capacity = ms = 40
×
0.2
=
8
c
a
l
/
0
K
8
c
a
l
=
4.2
×
8
J
=
33.6
j
o
u
l
e
/
0
K
.