There is a hole in the bottom of a tank containing water. If total pressure at the bottom is 3 atm (1 atm =105 N m -2) , then the velocity of water flowing from the hole is (outside pressure is zero)

Question

There is a hole in the bottom of a tank containing water. If total pressure at the bottom is 3 atm (1 atm =105 N m -2) , then the velocity of water flowing from the hole is (outside pressure is zero) (A) √400ms- 1 (B) √600ms- 1 (C) √60ms- 1 (D) None of these

Tardigrade Admin · Accepted Answer

Pressure at the bottom of the tank is given by P=hÏg=3× 105Nm- 2 and velocity of water is given by v=√2 gh . ∴ textv = √(2 textP/ρ ) = √(2 × 3 × 1 05/1 03) = √6 0 0 textm / texts

Q. There is a hole in the bottom of a tank containing water. If total pressure at the bottom is $3 a t m$ $(1 a t m = 1 0^{5} N m^{- 2})$ , then the velocity of water flowing from the hole is (outside pressure is zero)

$400 m s^{- 1}$

$600 m s^{- 1}$

$60 m s^{- 1}$

None of these

Pressure at the bottom of the tank is given by $P = h ρ g = 3 \times 1 0^{5} N m^{- 2}$ and velocity of water is given by $v = 2 g h$ .
$∴ v = \frac{2 P}{ρ} = \frac{2 \times 3 \times 1 0 ^{5}}{1 0 ^{3}} = 600 m / s$

Q. There is a hole in the bottom of a tank containing water. If total pressure at the bottom is 3atm (1atm=105Nm−2) , then the velocity of water flowing from the hole is (outside pressure is zero)

400​ms−1

600​ms−1

60​ms−1