Question

There is a hole in the bottom of a tank containing water. If total pressure at the bottom is $3 \, atm$ $\left(1 atm =10^5 \quad N m ^{-2}\right)$ , then the velocity of water flowing from the hole is (outside pressure is zero)

• A. $\sqrt{400}ms^{- 1}$
• B. $\sqrt{600}ms^{- 1}$
• C. $\sqrt{60}ms^{- 1}$
• D. None of these

Answer 1

Answer: (B)

Pressure at the bottom of the tank is given by $P=hρg=3\times 10^{5}Nm^{- 2}$ and velocity of water is given by $v=\sqrt{2 gh}$ .
$\therefore \text{v} = \sqrt{\frac{2 \text{P}}{\rho }} = \sqrt{\frac{2 \times 3 \times 1 0^{5}}{1 0^{3}}} = \sqrt{6 0 0} \text{m} / \text{s}$