There is a current of 0.21 A in a copper wire whose area of cross-section is 10-6 m 2. If the number of free electrons per m 3 is 8.4 × 1028, then find the drift velocity, (e=1.6 × 10-19 C )

Question

There is a current of 0.21 A in a copper wire whose area of cross-section is 10-6 m 2. If the number of free electrons per m 3 is 8.4 × 1028, then find the drift velocity, (e=1.6 × 10-19 C ) (A) 2 × 10-5 ms -1 (B) 1.56 × 10-5 ms -1 (C) 1 × 10-5 ms -1 (D) 0.64 × 10-5 ms -1

Tardigrade Admin · Accepted Answer

vd =i / n A e=0.21 /(8.4 × 1028 × 10-6 × 1.6 × 10-19) =1.56 × 10-5 ms -1

Q. There is a current of $0.21 A$ in a copper wire whose area of cross-section is $1 0^{- 6} m^{2}$ . If the number of free electrons per $m^{3}$ is $8.4 \times 1 0^{28}$ , then find the drift velocity, $(e = 1.6 \times 1 0^{- 19} C)$

$2 \times 1 0^{- 5} m s^{- 1}$

$1.56 \times 1 0^{- 5} m s^{- 1}$

$1 \times 1 0^{- 5} m s^{- 1}$

$0.64 \times 1 0^{- 5} m s^{- 1}$

$v_{d} = i / n A e = 0.21/ (8.4 \times 1 0^{28} \times 1 0^{- 6} \times 1.6 \times 1 0^{- 19})$
$= 1.56 \times 1 0^{- 5} m s^{- 1}$

Q. There is a current of 0.21A in a copper wire whose area of cross-section is 10−6m2. If the number of free electrons per m3 is 8.4×1028, then find the drift velocity, (e=1.6×10−19C)

2×10−5ms−1

1.56×10−5ms−1

1×10−5ms−1

0.64×10−5ms−1