There are two common oxides of sulphur, one of which contains 50 % O 2 by weight, the other almost exactly 60 %. The weights of sulphur which combine with 1 g of O 2 (fixed) are in the ratio of

Question

There are two common oxides of sulphur, one of which contains 50 % O 2 by weight, the other almost exactly 60 %. The weights of sulphur which combine with 1 g of O 2 (fixed) are in the ratio of (A) 1: 1 (B) 2: 1 (C) 2: 3 (D) 3: 2

Tardigrade Admin · Accepted Answer

First oxide Second oxide Sulphur 50 % 40 % Oxygen 50 % 60 % In first oxide 1 parts oxygen combines with sulphur =(50/50)=1 Similarly for second oxide =(40/60)=0.67 So the ratio is 1: 0.67 or 3: 2

First oxide	Second oxide
Sulphur $50%$	$40%$
Oxygen $50%$	$60%$

Q. There are two common oxides of sulphur, one of which contains $50% O_{2}$ by weight, the other almost exactly $60%$ . The weights of sulphur which combine with $1 g$ of $O_{2}$ (fixed) are in the ratio of

1 : 1

2 : 1

2 : 3

3 : 2

First oxide Second oxide

Sulphur $50%$ $40%$

Oxygen $50%$ $60%$

In first oxide 1 parts oxygen combines with sulphur $= \frac{50}{50} = 1$

Similarly for second oxide $= \frac{40}{60} = 0.67$

So the ratio is $1 : 0.67$ or $3 : 2$

Q. There are two common oxides of sulphur, one of which contains 50%O2​ by weight, the other almost exactly 60%. The weights of sulphur which combine with 1g of O2​ (fixed) are in the ratio of