Q. There are two common oxides of sulphur, one of which contains $50 \% O _{2}$ by weight, the other almost exactly $60 \%$. The weights of sulphur which combine with $1 \,g$ of $O _{2}$ (fixed) are in the ratio of
Some Basic Concepts of Chemistry
Solution:
First oxide
Second oxide
Sulphur $50 \%$
$40 \%$
Oxygen $50 \%$
$60 \%$
In first oxide 1 parts oxygen combines with sulphur $=\frac{50}{50}=1$
Similarly for second oxide $=\frac{40}{60}=0.67$
So the ratio is $1: 0.67$ or $3: 2$
| First oxide | Second oxide |
|---|---|
| Sulphur $50 \%$ | $40 \%$ |
| Oxygen $50 \%$ | $60 \%$ |