Q.
There are three samples of H2O2 labelled as 10vol;15vol;20vol. Half litre of each sample is mixed and then diluted with equal volume of water. Calculate volume strength of the resultant solution.
We know, V=5.6×N N1=5.610;N2=5.615;N3=5.620 N1V1+N2V2+N3V3=NRVR 5.610×21+5.615×21+5.620×21=NR×3
or NR=1.339
or V=NR×5.6=1.339×5.6=7.5