Question

There are three samples of $H_{2}O_{2}$ labelled as $10 vol; 15 vol; 20 vol$. Half litre of each sample is mixed and then diluted with equal volume of water. Calculate volume strength of the resultant solution.

• A. $1.339$
• B. $7.5$
• C. $5.0$
• D. $2.68$

Answer 1

Answer: (B)

We know, $V =5.6 \times N$
$N_{1} =\frac{10}{5.6}; N_{2} = \frac{15}{5.6}; N_{3} =\frac{20}{5.6}$
$N_{1} V_{1} + N_{2} V_{2} + N_{3} V_{3} = N_{R} V_{R}$
$ \frac{10}{5.6} \times \frac{1}{2} +\frac{15}{5.6} \times \frac{1}{2} + \frac{20}{5.6} \times\frac{1}{2} = N_{R} \times3$
or $N_{R} = 1.339$
or $V = N_{R} \times 5.6 = 1.339 \times5.6 = 7.5$