The work done when two moles of an ideal gas is compressed from a volume of 5 m 3 to 1 dm 3 at 300 K, under a pressure of 100 Pa is:

Question

The work done when two moles of an ideal gas is compressed from a volume of 5 m 3 to 1 dm 3 at 300 K, under a pressure of 100 Pa is: (A) 499.9 kJ (B) -499.9 kJ (C) -99.5 kJ (D) 42495 kJ

Tardigrade Admin · Accepted Answer

Work done ; w=-P text ext (V2-V1) Here; P text ext =100 Pa V 1 =5 m 3=5 × 103 L ⇒ V 2=1 dm 3=1 L W =-100 ×(1-5000)=499900 K Pa L = 499900 J =499.9 kJ

Q. The work done when two moles of an ideal gas is compressed from a volume of $5 m^{3}$ to $1 d m^{3}$ at $300 K$ , under a pressure of $100 P a$ is:

499.9 kJ

-499.9 kJ

-99.5 kJ

42495 kJ

Work done $; w = - P_{ext} (V_{2} - V_{1})$

Here; $P_{ext} = 100 P a$

$V_{1} = 5 m^{3} = 5 \times 1 0^{3} L$

$\Rightarrow V_{2} = 1 d m^{3} = 1 L$

$W = - 100 \times (1 - 5000) = 499900 K P a L$

$= 499900 J = 499.9 k J$

Q. The work done when two moles of an ideal gas is compressed from a volume of 5m3 to 1dm3 at 300K, under a pressure of 100Pa is: