The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2 m is 2 J . The potential difference between the two points will be (in volt)

Question

The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2 m is 2 J . The potential difference between the two points will be (in volt) (A) 0.2 (B) 8 (C) 0.1 (D) 0.4

Tardigrade Admin · Accepted Answer

By using W=Q . Δ V ⇒ Δ V=(2/20)=0.1 volt

Q. The work done in bringing a $20$ coulomb charge from point $A$ to point $B$ for distance $0.2 m$ is $2 J .$ The potential difference between the two points will be (in volt)

0.2

8

0.1

0.4

By using $W = Q .Δ V$
$\Rightarrow Δ V = \frac{2}{20} = 0.1$ volt

Q. The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2m is 2J. The potential difference between the two points will be (in volt)

0.2

8

0.1

0.4

By using W=Q.ΔV ⇒ΔV=202​=0.1 volt

Q. The work done in bringing a $20$ coulomb charge from point $A$ to point $B$ for distance $0.2 m$ is $2 J .$ The potential difference between the two points will be (in volt)

By using $W = Q .Δ V$
$\Rightarrow Δ V = \frac{2}{20} = 0.1$ volt