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  4. The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2 m is 2 J . The potential difference between the two points will be (in volt)

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Q. The work done in bringing a $20$ coulomb charge from point $A$ to point $B$ for distance $0.2\, m$ is $2\, J .$ The potential difference between the two points will be (in volt)

Electrostatic Potential and Capacitance

Solution:

By using $W=Q . \Delta V$
$\Rightarrow \Delta V=\frac{2}{20}=0.1$ volt