The work done in blowing a soap bubble of surface tension 0.06 × Nm-1 from 2 cm radius to 5 cm radius is.

Question

The work done in blowing a soap bubble of surface tension 0.06 × Nm-1 from 2 cm radius to 5 cm radius is. (A) 0.004168 J (B) 0.003168 J (C) 0.003158 J (D) 0.004568 J

Tardigrade Admin · Accepted Answer

Δ W = S ×Δ A = 0.06 ×4π(r22 - r21) = 0.003168 J

Q. The work done in blowing a soap bubble of surface tension $0.06 \times N m^{- 1}$ from $2 c m$ radius to $5 c m$ radius is.

0.004168 J

0.003168 J

0.003158 J

0.004568 J

$Δ W = S \times Δ A$
$= 0.06 \times 4 π (r_{2}^{2} - r_{1}^{2})$
$= 0.003168 J$

Q. The work done in blowing a soap bubble of surface tension 0.06×Nm−1 from 2cm radius to 5cm radius is.