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  4. The work done in blowing a soap bubble of surface tension 0.06 × Nm-1 from 2 cm radius to 5 cm radius is.

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Q. The work done in blowing a soap bubble of surface tension $ 0.06 × Nm^{-1}$ from $2 \,cm$ radius to $5 \,cm$ radius is.

BITSATBITSAT 2014

Solution:

$\Delta W = S \times\Delta A$
$ = 0.06 \times4\pi\left(r^{2}_{2} - r^{2}_{1}\right)$
$ = 0.003168 \,J $