The weight of a man in a lift, moving upwards is 608 N while the weight of the same man in the lift moving downwards, with the same acceleration, is 368 N. His normal weight in newton is:

Question

The weight of a man in a lift, moving upwards is 608 N while the weight of the same man in the lift moving downwards, with the same acceleration, is 368 N. His normal weight in newton is: (A) 488 (B) 588 (C) 480 (D) 240

Tardigrade Admin · Accepted Answer

If the lift is moving upwards with acceleration a, then m(g+a)=608 textN ?(i) If the lift is moving downwards with an acceleration a, then m(g-a)=368N ?(ii) Now, adding Eqs. (i) and (ii), we get 2mg=608+368=976 mg=488 kg

Q. The weight of a man in a lift, moving upwards is 608 N while the weight of the same man in the lift moving downwards, with the same acceleration, is 368 N. His normal weight in newton is:

488

588

480

240

If the lift is moving upwards with acceleration a, then $m (g + a) = 608 N$ ?(i) If the lift is moving downwards with an acceleration a, then $m (g - a) = 368 N$ ?(ii) Now, adding Eqs. (i) and (ii), we get $2 m g = 608 + 368 = 976$ $m g = 488 k g$

Q. The weight of a man in a lift, moving upwards is 608 N while the weight of the same man in the lift moving downwards, with the same acceleration, is 368 N. His normal weight in newton is:

488

588

480

240

If the lift is moving upwards with acceleration a, then m(g+a)=608N ?(i) If the lift is moving downwards with an acceleration a, then m(g−a)=368N ?(ii) Now, adding Eqs. (i) and (ii), we get 2mg=608+368=976 mg=488kg

If the lift is moving upwards with acceleration a, then $m (g + a) = 608 N$ ?(i) If the lift is moving downwards with an acceleration a, then $m (g - a) = 368 N$ ?(ii) Now, adding Eqs. (i) and (ii), we get $2 m g = 608 + 368 = 976$ $m g = 488 k g$