The wavelength of a spectral line in Lyman series, when electron jumps back from 2nd orbit, is

Question

The wavelength of a spectral line in Lyman series, when electron jumps back from 2nd orbit, is (A) 1162 mathringA (B) 1216 mathringA (C) 1362 mathringA (D) 1176 mathringA

Tardigrade Admin · Accepted Answer

(1/λ)=RH[(1/n12)-(1/n22)] For Lyman series n1=1, n2=2 (1/λ)=10,9678[(1/(1)2)-(1/(2)2)] =(10,9678 × 3/4) λ =1216 mathringA

Q. The wavelength of a spectral line in Lyman series, when electron jumps back from $2 n d$ orbit, is

$1162 \overset{˚}{A}$

$1216 \overset{˚}{A}$

$1362 \overset{˚}{A}$

$1176 \overset{˚}{A}$

$\frac{1}{λ} = R_{H} [\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}]$
For Lyman series $n_{1} = 1, n_{2} = 2$
$\frac{1}{λ} = 10, 9678 [\frac{1}{( 1 ) ^{2}} - \frac{1}{( 2 ) ^{2}}]$
$= \frac{10 , 9678 \times 3}{4}$
$λ = 1216 \overset{˚}{A}$

Q. The wavelength of a spectral line in Lyman series, when electron jumps back from 2nd orbit, is

1162A˚

1216A˚

1362A˚

1176A˚