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  4. The wavelength of a spectral line in Lyman series, when electron jumps back from 2nd orbit, is

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Q. The wavelength of a spectral line in Lyman series, when electron jumps back from $2nd$ orbit, is

J & K CETJ & K CET 2007Structure of Atom

Solution:

$\frac{1}{\lambda}=R_{H}\left[\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right]$
For Lyman series $n_{1}=1, n_{2}=2$
$\frac{1}{\lambda}=10,9678\left[\frac{1}{(1)^{2}}-\frac{1}{(2)^{2}}\right]$
$=\frac{10,9678 \times 3}{4}$
$\lambda =1216\,\mathring{A}$