The waveforms A and B given below axe given as input to a NAND gate. Then its logic output Y is Voltage

Question

The waveforms A and B given below axe given as input to a NAND gate. Then its logic output Y is Voltage (A) for t1 to t2; Y = 0 (B) for t2 to t3; Y = 1 (C) for t3 to t4; Y = 1 (D) for t4 to t5; Y = 0

Tardigrade Admin · Accepted Answer

Time A B Y = overline AB t 1 1 0 1 t 2 1 1 0 t 3 1 1 0 t 4 0 1 1 t5 0 0 1 t6 1 1 0 NAND gate is the combination of AND and NOT gate and the output of the two inputs (A and B) NAND gate is Y = overline AB Here, the truth table for the NAND gate will be the following table, (note 1 for high signal and o for low signal)

Time	$A$	$B$	$Y = \overline{A B}$
$t_{1}$	1	0	1
$t_{2}$	1	1	0
$t_{3}$	1	1	0
$t_{4}$	0	1	1
$t_{5}$	0	0	1
$t_{6}$	1	1	0

Q. The waveforms A and B given below axe given as input to a NAND gate. Then its logic output Y is Voltage

for $t_{1} t o t_{2}; Y = 0$

for $t_{2} t o t_{3}; Y = 1$

for $t_{3} t o t_{4}; Y = 1$

for $t_{4} t o t_{5}; Y = 0$

Q. The waveforms A and B given below axe given as input to a NAND gate. Then its logic output Y is Voltage

for t1​tot2​;Y=0

for t2​tot3​;Y=1

for t3​tot4​;Y=1

for t4​tot5​;Y=0

for $t_{1} t o t_{2}; Y = 0$

for $t_{2} t o t_{3}; Y = 1$

for $t_{3} t o t_{4}; Y = 1$

for $t_{4} t o t_{5}; Y = 0$