The wave number of the first line of Balmer series of hydrogen is 15200 cm-1. The wave number of the corresponding line of Li2+ ion is

Question

The wave number of the first line of Balmer series of hydrogen is 15200 cm-1. The wave number of the corresponding line of Li2+ ion is (A) 15200 cm-1 (B) 60800 cm-1 (C) 76000 cm-1 (D) 136800 cm-1

Tardigrade Admin · Accepted Answer

barv (Li2+) =z2 ×15200 cm-1 =32 ×15200 cm-1 =9×15200 cm-1 =136800 cm-1

Q. The wave number of the first line of Balmer series of hydrogen is $15200 c m^{- 1}$ . The wave number of the corresponding line of $L i^{2 +}$ ion is

$15200 c m^{- 1}$

$60800 c m^{- 1}$

$76000 c m^{- 1}$

$136800 c m^{- 1}$

$\overset{v}{ˉ} (L i^{2 +}) = z^{2} \times 15200 c m^{- 1}$
$= 3^{2} \times 15200 c m^{- 1}$
$= 9 \times 15200 c m^{- 1}$
$= 136800 c m^{- 1}$

Q. The wave number of the first line of Balmer series of hydrogen is 15200cm−1. The wave number of the corresponding line of Li2+ ion is

15200cm−1

60800cm−1

76000cm−1

136800cm−1