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Chemistry
The wave number of the first line of Balmer series of hydrogen is 15200 cm-1. The wave number of the corresponding line of Li2+ ion is
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Q. The wave number of the first line of Balmer series of hydrogen is $15200\, cm^{-1}$. The wave number of the corresponding line of $Li^{2+}$ ion is
Structure of Atom
A
$15200\, cm^{-1}$
37%
B
$60800\, cm^{-1}$
21%
C
$76000 \,cm^{-1}$
17%
D
$136800\, cm^{-1}$
26%
Solution:
$\bar{v} \left(Li^{2+}\right) =z^{2} \times15200 \,cm^{-1}$
$ =3^{2} \times15200 \,cm^{-1} $
$=9\times15200\, cm^{-1} $
$=136800 \,cm^{-1}$