Question

The volume versus temperature graph of $1$ mole of an ideal gas is given below

The pressure of the gas (in atm) at $X$ , $Y$ and $Z,$ respectively, are

• A. $0.328,0.820,0.820$
• B. $3.28,8.20,3.28$
• C. $0.238,0.280,0.280$
• D. $32.8,0.280,82.0$

Answer 1

Answer: (A)

According to ideal gas equation
$pV=nRT$
For 1 mole, $n=1$
$\therefore pV=RT$
$\Rightarrow p=\frac{RT}{V}$
For gas $X$,
$V=50L,T=200K$
$\therefore$ Pressure of gas $X=\frac{0.0821\times 200}{50}$
$=0.328$ atm
for gas $Y$
$V=50L,=500K$
$\therefore$ Pressure of gas $Y=\frac{0.0821\times 500}{50}$
$=0.821$ atm
for gas $Z,$
$V=20L,T=200K$
$\therefore$ Pressure of gas $Z=\frac{0.0821\times 200}{20}$
$0.821atm$