Question

The volume of $2.8gm$ of carbon monoxide at $27^{\circ }C$ and $0.821atm$ pressure is $[R=0.0821$ litre atm $mo{l}^{-1}{K}^{-1}$ ]:

• A. 0.5 litre
• B. 1.5 litre
• C. 3 litre
• D. 6 litre

Answer 1

Answer: (C)

The volume of carbon monoxide $=\frac{nRT}{P}$
Mass of carbon monoxide $=2.8g$
$P=0.821$ atm,
$T=27+273=300K$
$R=0.0821$
$\because$ gram molecular weight of
$CO=12+16=28$
$\therefore$ number of moles in $2.8g$ of $CO=\frac{2.8}{28}=0.1$
$\therefore$ volume $=\frac{0.1\times 0.0821\times 300}{0.821}=3$ litre