Question

The volume of $2.8 \,gm$ of carbon monoxide at $ 27^{\circ} C $ and $0.821 \,atm$ pressure is $[R = 0.0821$ litre atm $ mol^{-1}K^{-1} $ ]:

• A. 0.5 litre
• B. 1.5 litre
• C. 3 litre
• D. 6 litre

Answer 1

Answer: (C)

The volume of carbon monoxide $=\frac{n R T}{P}$
Mass of carbon monoxide $=2.8 \,g$
$P=0.821$ atm,
$T=27+273=300 \,K$
$R=0.0821$
$\because$ gram molecular weight of
$C O=12+16=28$
$\therefore $ number of moles in $2.8 \,g$ of $C O=\frac{2.8}{28}=0.1$
$\therefore $ volume $=\frac{0.1 \times 0.0821 \times 300}{0.821}=3$ litre