The volume of 0.1N dibasic acid sufficient to neutralize 1 g of a base that furnishes 0.04 mole of OH- in aqueous solution is :

Question

The volume of 0.1N dibasic acid sufficient to neutralize 1 g of a base that furnishes 0.04 mole of OH- in aqueous solution is : (A) 200 mL (B) 400 mL (C) 600 mL (D) 800 mL

Tardigrade Admin · Accepted Answer

Law of equivalance (Apply) equivalance of acid = equivalance of base 0.1× v = 0.04×1 v = 0.4 L = 0.4×1000 = 400 ml

Q. The volume of 0.1N dibasic acid sufficient to neutralize 1 g of a base that furnishes 0.04 mole of $O H^{-}$ in aqueous solution is :

200 mL

400 mL

600 mL

800 mL

Law of equivalance (Apply)
equivalance of acid = equivalance of base
$0.1 \times v = 0.04 \times 1$
$v = 0.4 L$
$= 0.4 \times 1000 = 400 m l$

Q. The volume of 0.1N dibasic acid sufficient to neutralize 1 g of a base that furnishes 0.04 mole of OH− in aqueous solution is :