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Q. The volume of 0.1N dibasic acid sufficient to neutralize 1 g of a base that furnishes 0.04 mole of $OH^{-}$ in aqueous solution is :

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Solution:

Law of equivalance (Apply)
equivalance of acid = equivalance of base
$0.1\times v = 0.04\times1$
$v = 0.4\,L$
$= 0.4\times1000 = 400\,ml$