The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is

Question

The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is (A)  20π s  (B)  2π  (C)  (2π /10)s  (D)  200π s

Tardigrade Admin · Accepted Answer

T=2π √(l/g) =2π √(9.8/980) =2π √(1/100) =(2π /10)s

Q. The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is

$20 π s$

$2 π$

$\frac{2 π}{10} s$

$200 π s$

$T = 2 π \frac{l}{g}$ $= 2 π \frac{9.8}{980}$ $= 2 π \frac{1}{100}$ $= \frac{2 π}{10} s$

Q. The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is

20πs

2π

102π​s

200πs

T=2πgl​​ =2π9809.8​​ =2π1001​​ =102π​s

$20 π s$

$2 π$

$\frac{2 π}{10} s$

$200 π s$

$T = 2 π \frac{l}{g}$ $= 2 π \frac{9.8}{980}$ $= 2 π \frac{1}{100}$ $= \frac{2 π}{10} s$