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Q. The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is

MGIMS WardhaMGIMS Wardha 2007

Solution:

$ T=2\pi \sqrt{\frac{l}{g}} $ $ =2\pi \sqrt{\frac{9.8}{980}} $ $ =2\pi \sqrt{\frac{1}{100}} $ $ =\frac{2\pi }{10}s $