The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is :

Question

The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is : (A) 200 π sec (B) 2 π /10 sec (C) 2 π sec (D) 4 π sec

Tardigrade Admin · Accepted Answer

Time period of oscillation T=2π √(Δ l/g) =2π √(9.8× 10-2/9.8)=(2π /10) sec

Q. The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is :

200 $π$ sec

2 $π$ /10 sec

2 $π$ sec

4 $π$ sec

Time period of oscillation $T = 2 π \frac{Δ l}{g}$ $= 2 π \frac{9.8 \times 10 ^{- 2}}{9.8} = \frac{2 π}{10} sec$

Q. The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is :

200 π sec

2 π /10 sec

2 π sec

4 π sec

Time period of oscillation T=2πgΔl​​ =2π9.89.8×10−2​​=102π​sec

200 $π$ sec

2 $π$ /10 sec

2 $π$ sec

4 $π$ sec

Time period of oscillation $T = 2 π \frac{Δ l}{g}$ $= 2 π \frac{9.8 \times 10 ^{- 2}}{9.8} = \frac{2 π}{10} sec$